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Q.

If A+B+C=π , then the value of  cosAsinBsinC+cosBsinAsinC+cosCsinAsinB  is ____

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a

answer is B.

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Detailed Solution

A+B+C=π

sin2A+sin2B+sin2C=4sinA.sinB.sinC

cosAsinB.sinC+cosBsinC.sinA+cosCsinA.sinB=2(cosA.sinA+cosBsinB+cosCsinC)2(sinA.sinB.sinC)

sin2θ=2sinθ.cosθ

=sin2A+sin2B+sin2C2(sinA.sinB.sinC)

=4sinA.sinB.sinC2sinA.sinB.sinC=2

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