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Q.

If $Δ ABC$ is a right angled triangle, right angled at $'C'$ , then $\frac{1}{\log_{c + b} a} + \frac{1}{\log_{c - b} a} =$

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a

0

b

1

c

2

d

3

answer is A.

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Detailed Solution

\frac{1}{\log_{c + b} a} + \frac{1}{\log_{c - b} a}

$\log_{a} (c + b) + \log_{a} (c - b) = \log_{a} (c^{2} - b^{2})$

$c^{2} = a^{2} + b^{2}$

$c^{2} - b^{2} = a^{2}$

$\log_{a} a^{2} = 2 \log_{a} a = 2$

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