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Q.

If  a+b+c = 5   and ab+bc+ca = 10  then a 3 + b 3 + c 3 3abc    is


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a

25

b

0

c

-25

d

24 

answer is C.

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Detailed Solution

By the given problem, the values of a+b+c   is 5 and ab+bc+ca  is 10.
Factorizing the expression by breaking it using the following standard algebraic identity: Question Image ,
we get,
Question Image Substituting the values of the terms a+b+c   and ab+bc+ca  , we can calculate the value of ( a 2 + b 2 + c 2  ).
(a+b+c) 2 = a 2 + b 2 + c 2 +2 ab+bc+ca 5 2 = a 2 + b 2 + c 2 +2(10) 25= a 2 + b 2 + c 2 +20 2520= a 2 + b 2 + c 2 5= a 2 + b 2 + c 2  
Substituting the given values to calculate the value of the expression, we get,
Question Image  Hence, the value of a 3 + b 3 + c 3 3abc   is -25.
Therefore, option 3 is correct.
 
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If  a+b+c = 5   and ab+bc+ca = 10  then a 3 + b 3 + c 3 −3abc    is