Q.

If a,b,c are three natural numbers in A.P and a+b+c=21then the possible number of values of the ordered triplet a,b,c is

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answer is 13.

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Detailed Solution

a+a+d+a+2d=21a+d=7b=7 a+c=14 
The number of positive integral solutions of (a+c=14) is 13

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