If ABCD is an isosceles trapezium, ∠C is equal to

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∠B

∠A

∠D

°

answer is C.

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Detailed Solution

We know that trapezium is a convex quadrilateral with at least one pair of sides that is parallel to each other. If the quadrilateral AB and CD are parallel to each other then we write the name of the quadrilateral is ABCD.
The sides which are not parallel to each other are called legs of the trapezium. The pair of adjacent angles at the two consecutive vertices of parallel sides are called base angles.
We know that isosceles trapezium is a trapezium where the legs are of equal length and base angles are of equal measure.
We are given the question that ABCD is an isosceles trapezium and are asked to which angle the measure of ∠C is equal to. Since ABCD is trapezium by conventional naming the parallel sides are AB and CD which means AB||CD
The sides that are not parallel are AD and BC and hence they will be equal length that is AD=BC
So the adjacent angles on the parallel side AB are ∠A, ∠B and the adjacent angles on the parallel side CD are ∠C, ∠D. So these are base angle and hence they are of equal measure which means’
∠A=∠B
∠C=∠D
So the correct option is 3.

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