If ΔABC∼ΔPQR , such that m ∠A=50° and m ∠B=60° , then m ∠R=

ΔABC∼ΔPQR ∠R=180°−(∠A+∠B) =180°−(50°+60°) =180°−110° =70°

ΔABC∼ΔPQR ∠R=180°−(∠A+∠B) =180°−(50°+60°) =180°−110° =70°

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If $Δ A B C \sim Δ P Q R$ , such that $m ∠ A = 50 °$ and $m ∠ B = 60 °$ , then $m ∠ R =$

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50 °

60 °

70 °

90 °

answer is D.

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Δ A B C \sim Δ P Q R

$∠ R = 180 ° - (∠ A + ∠ B)$

$= 180 ° - (50 ° + 60 °)$

$= 180 ° - 110 °$

$= 70 °$

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