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Q.

If acosθbsinθ=c, then asinθ+bcosθ=

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a

±a2+b2c2

b

±a2b2+c2

c

±b2c2a2

d

±a2+b2+c2

answer is A.

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Detailed Solution

acosθbsinθ=c

asinθ+bcosθ=?

acosθbsinθ=c

asinθ+bcosθ=k

acosθbsinθ=c

(acosθbsinθ)2=c2

asinθ+bcosθ=k

(asinθ+bcosθ)2=k2

c2+k2=a2cos2θ+b2sin2θ

+a2sin2θ+b2cos2θ

c2+k2=a2+b2

k2=a2+b2c2

k=±a2+b2c2

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