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Q.

If Adj 102112021=5a211022b then [a, b] =

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a

[4,1]

b

[-4,-1]

c

[4,-1]

d

[-4,1]

answer is C.

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Detailed Solution

a = (-1)2+1(0-4) = 4 
b = (-1)3+3(1-0) = 1

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If Adj 102−11−2021=5a−2110−2−2b then [a, b] =