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If all the six digit numbers $x_{1} x_{2} x_{3} x_{4} x_{5} x_{6}$ with $0 < x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6}$ are arranged in the increasing order, then the sum of the digits in the $84^{t h}$ number is _______

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answer is 39.

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Detailed Solution

$84^{t h}$ number = 456789

sum of digits = 4 + 5 + 6 + 7 + 8 + 9 = 39

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