If all the $F$ atoms are replaced by $' O'$ atom from ${SF}^{4}$ without changing the covalency of $' S'$ atom then, which of the following property undergoes change in the process?

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Oxidation state of 'S' atom

Number of lone pairs on 'S' atom

Hybridization of 'S' atom

d-orbital participation in bonding

answer is C.

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Detailed Solution

In SF₄ molecule, 4 bond pair and 1 lone pair is present. The arrangement is trigonal bipyramidal. So, the Hybridization of 'S' atom.

Hence, the correct option is C.

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