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If an air bubble rises from the bottom of a mercury tank to the top its volume becomes 1/2 times the initial volume . When normal pressure is 76cm of Hg then the depth of the Hg tank is

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76 cm

132 cm

49 cm

38 cm

answer is A.

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Detailed Solution

$p_{1} v_{2} = p_{2} v_{2} a t b o t t e m h ρ g \times V = a t t h e t o p 76 ρ g \times \frac{V}{2} h = 38$

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