Q.

If an angle A of ABC satisfies 5COSA+3=0 then the roots of the quadratic equation 9x2+27x+20=0  are

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a

TanA , CosA

b

SecA , TanA

c

SinA , SecA

d

SecA , CosA

answer is B.

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Detailed Solution

Given 5CosA+3=0CosA=-35

Given equation 9x2+27x+20=0 9x2+15x+12x+20=0 3x(3x+5)+4(3x+5)=0 (3x+5)(3x+4)=0 x=-53=SecA and x=-43=TanA

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