If an angle and a side of a right angle triangle is known, then rest of the sides and angles can be found as follows
In $∆$ABC (Figure 1), if $\mathrm{\angle }B={90}^{\circ },\mathrm{\angle }C=\theta$ and BC = x, then $\mathrm{AB}=\mathrm{xtan}\mathrm{\theta }\text{ and }\mathrm{AC}=\mathrm{xsec}\mathrm{\theta }$
 

 Now, consider an isosceles triangle P Q R  (Fig 2),
 

where PQ = PR and 20N = $\sqrt{3}$
On the basis of above information answer the following