If an angle is 60^o less than two times its supplement, then the greater angle is __________.

Let us assume the angle is P.

Then, its supplement is 180^o – P.

As per the condition in the question,

P = 2(180^o – P) – 60^o

P = 360^o – 2P – 60^o

P + 2P = 300^o

3P = 300^o

P = $\frac{{300}^0}{3}$

P = 100^o

So, its supplement is 180^o – P = 180^o – 100^o = 80^o

Therefore, the greater angle is 100^o.