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If an artificial satellite moves in a circular orbit of radius $42250 km$ , calculate the speed if it takes $24$ hours to complete one revolution.

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2.36 km / s

5.32 km / s

3.07 km / s

11065.4 km / s

answer is C.

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Detailed Solution

The speed will be

3.07 km / s

.
Given:
We know that the speed of the object moving in the circular orbit is given by the formula,

v = \frac{2 πr}{t}

Now using the given credentials, we have

π = \frac{22}{7}

Radius

r = 42250 km

Time

t = 24 h

speed = \frac{2 \times 22 \times 42250}{7 \times 24}

Therefore

v = 11065.4 km / h

Since we need the answers in seconds

v = \frac{11065.4}{60 \times 60}

v = 3.07 km / s

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