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If an electric refrigerator rated $400 W$ operates $8 hours$ per day, then [[1]] $kWh$ energy needed to operate it for $30 days$ .

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Detailed Solution

If an electric refrigerator rated

400 W

operates

8 hours

per day, then

96 kWh

energy needed to operate it for

30 days

. Given,

Power (P) = 400 W

………………… (i)

Time (t) = 8 Hr per day

Then for

30 days

time will become

(t) = 30 \times (8 h)

= 240 h

……………………. (ii)
Thus, the energy consumed (in kWh) by the refrigerator in

30

days can be calculated by the formula.

Energy (E) = Power \times Time

……………… (iii)
Now put the above values of equations (i), (ii) in equation (iii) we get,

= > E = (400 W) (240 h)

= > E = 96000 Wh

= > E = 96 kWh

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