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If an electron enters into a space between the plates of a parallel plate capacitor at an angle $α$ with the plates and leaves at angle $β$ to the plates. The ratio of its kinetic energy while entering the capacitor to that while leaving will be :

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${[\frac{\cos β}{\cos α}]}^{2}$

${[\frac{\sin α}{\sin β}]}^{2}$

${[\frac{\cos α}{\cos β}]}^{2}$

${[\frac{\sin β}{\sin α}]}^{2}$

answer is B.

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Detailed Solution

The component of velocity parallel to plates remains constant since E is perpendicular to plates

$\Rightarrow ucos α = vcos β$

$\Rightarrow \frac{u}{v} = \frac{\cos β}{\cos α}$

$\Rightarrow \frac{K \cdot E_{i}}{K . E_{f}} = \frac{\cos^{2} β}{\cos^{2} α}$

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