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Q.

If an electron in hydrogen atom jumps from an orbit of level n = 3 to an orbit of level n = 2 , emitted radiation has a frequency (R = Rydberg's constant, c = velocity of light)

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a

$\frac{5 R c}{36}$

b

$\frac{R c}{25}$

c

$\frac{3 R c}{27}$

d

$\frac{8 R c}{9}$

answer is D.

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Detailed Solution

When an electron jumps from orbit n_i to orbit n_f (n_i > n_f), the frequency of emitted photon is given by

$v = c R (\frac{1}{n_{f}^{2}} - \frac{1}{n_{i}^{2}})$

$\Rightarrow v = c R (\frac{1}{2^{2}} - \frac{1}{3^{2}})$

$v = c R (\frac{5}{36}) \Rightarrow v = \frac{5 c R}{36}$

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If an electron in hydrogen atom jumps from an orbit of level n = 3 to an orbit of level n = 2 , emitted radiation has a frequency (R = Rydberg's constant, c = velocity of light)