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Q.

If an emitter current is changed by 4 mA, the collector current changes by 3.5 mA. The value of $β$ will be :

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a

7

b

3.5

c

0.875

d

0.5

answer is C.

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Detailed Solution

$\begin{array}{l} {ΔI}_{E} = 4 \\ {ΔI}_{C} = 3.5 \\ α = \frac{{ΔI}_{C}}{{ΔI}_{E}} = (\frac{3.5}{4}) = (\frac{7}{8}) \\ β = \frac{α}{1 - α} = \frac{\frac{7}{8}}{1 - \frac{7}{8}} = 7 \end{array}$

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