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Q.

If an error of 0.02 cm is made while measuring the radius 10 cms of a sphere, thenthe error in the volume is

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a

0.06 $π$ cubic cm

b

16 $π$ cubic cm

c

80 $π$ cubic cm

d

8 $π$ cubic cm

answer is A.

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Detailed Solution

$r = 10 δr = 0.02 v = \frac{4}{3} {πr}^{3} \Rightarrow δv = 4 {πr}^{2} δr = 4 π \times 100 \times 0.02 = 8 π$

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