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Q.

If an ideal transformer have turn ratio 5, frequency 50 Hz, root mean square value of potential difference on primary 100 volts and the resistance of the secondary winding is 500Ω, then the peak value of voltage across secondary winding will be (the efficiency of the transformer is hundred percent)

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a

502 volt

b

202 volt

c

102 volt

d

5002 volt

answer is A.

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Detailed Solution

Use v1v2=N1N2

⇒1002V2=15

⇒V2=5002 volt 

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