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Q.

If an object weights 270N at earth's surface, the weight of the object an altitude equal to twice the radius of earth is ________N

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answer is 30.

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Detailed Solution

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$\frac{W_{h}}{W} = \frac{g_{h}}{g} = {[\frac{R}{R + h}]}^{2}$

$\Rightarrow \frac{W_{h}}{270} = {[\frac{R}{R + 2 R}]}^{2} = \frac{1}{9}$

$\Rightarrow W_{h} = 30 N$

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