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Q.

If  α,β  are roots of Quadratic equation  x2+52x+10=0,α>β  and  Pn=αnβn  for each positive integer n then value of  P17.P20+52P17P19P18P19+52P182  is

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Detailed Solution

 α,β   are roots of  x2+52x+10=0
a+β=52                 Pn=αnβn   
Now   P17P20+52P17P19P18P19+52P182P17(P20+52P19)P18(P19+52P18)
P17P18.(α20β20+52(α19β19))(α19β19+52(α18β18)) P17P18.(α19(α+52)β19(β+52))(α18(α+52)β19(β+52))P17P18.[α19(β)β19(α)][α18(β)β18(α)]P17P18.αβ(α18β18)αβ(α17β17)P17P18.P18P17=1 

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