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Q.

If  α,β are roots of the equation ax2+bx+c=0  then the roots of the equation (2x+1)2−b(2x+1)(3−x)+c(3−x)2=0 are

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a

2α−1α−2, 2β+1β−2

b

2α+1α−3, 2β+1β−3

c

3α+1α−2, 3β+1β−2

d

none

answer is B.

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Detailed Solution

2x+1x−32+b2x+1x−3+c=0

α=2x+1x−3

αx−3α=2x+1x(α−2)=3α+1x=1+3αα−2

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