Q.

If α,β are the roots of the equation,x2x1=0 and Sn=2023αn+2024βn, then 

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a

S11=S10+S12

b

2S12=S11+S10

c

2S11=S12+S10

d

S12=S11+S10

answer is B.

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Detailed Solution

x2x1=0
Sn=2023αn+2024βn
Sn1+Sn2=2023αn1+2024βn1+2023αn2+2024βn2
=2023αn2[1+α]+2024βn2[1+β]
=2023αn2[α2]+2024βn2[β2]
=2023αn+2024βn
Sn1+Sn2=Sn
Put n=12
S11+S10=S12

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If α,β are the roots of the equation,x2−x−1=0 and Sn=2023αn+2024βn, then