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If $α, β, γ$ are the roots of the equation $x^{3} - p x^{2} + q x + r = 0$ then $(α + β) (β + γ) (γ + α) =$

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$r - p q$

$\frac{p^{2} - 2 q}{r^{2}}$

$2 (p^{2} - 3 q)$

$q p + r$

answer is C.

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Detailed Solution

$α + β = x \Rightarrow α + β + γ - γ = x \Rightarrow p - γ = x \Rightarrow γ = p - x P r o d u c t o f r o o t s o f f (p - x) = 0$

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