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If $α, β, γ$ are the rotos of $x^{3} + 2 x^{2} - 4 x - 3 = 0$ then the equation of whose roots are $\frac{α}{3}, \frac{β}{3}, \frac{γ}{3}$ is

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$x^{3} + 6 x^{2} - 36 x - 81 = 0$

$9 x^{3} + 6 x^{2} - 4 x - 1 = 0$

$9 x^{3} + 6 x^{2} + 4 x + 1 = 0$

$x^{3} - 6 x^{2} + 36 x + 81 = 0$

answer is B.

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Detailed Solution

$\begin{array}{l} α, β, γ \to f (x) = x^{3} + 2 x^{2} - 4 x - 3 = 0 \\ \frac{α}{3}, \frac{β}{3}, \frac{γ}{3} \to f (x) = ? \end{array}$
$f (3 x) = 0$ we get answer

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