If $\arg \left(\frac{z_1-\frac{3z}{\left|z\right|}}{\frac{-3z}{\left|z\right|}}\right)=\frac{\pi }{3}$ and  $|\frac{3z}{\left|z\right|}-z_1|=4$ then  $\left|{z_1}^2\right|$  is

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!