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If azimuthal quantum number could have value of also (in addition to normal value), then EC of Ti (Z = 22) would have been

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${1s}^{2} {,2s}^{2} {,2p}^{6} {,3s}^{2} {,3p}^{6} {,4s}^{2} {,3d}^{2}$

${1s}^{2} {,1p}^{6} {2s}^{2} {,2p}^{6} {,3s}^{2} {,3d}^{4}$

${1s}^{2} {,1p}^{6} {,2s}^{2} {,2p}^{6} {,3s}^{1} {,3d}^{5}$

${1s}^{2} {,1p}^{6} {,2s}^{2} {,2p}^{6} {,2d}^{6}$

answer is A.

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Detailed Solution

Ti (Z = 22) belongs to 1^st series of d – block elements it has two electrons in 3d – subshell hence its correct electronic configuration is ${1s}^{2} {,2s}^{2} {2p}^{6} {, 3s}^{2} {3p}^{6} {,4s}^{2} {, 3d}^{2}$

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