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If,

% B in the product is

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answer is A.

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Detailed Solution

$% B = \frac{k_{1}}{k_{1} + k_{2}} \times 100$

$\begin{array}{l} = \frac{2 \times 10^{3}}{2 \times 10^{3} + 6 \times 10^{3}} \times 100 \\ = \frac{2 \times 10^{3}}{8 \times 10^{3}} \times 100 \\ = \frac{100}{4} = 25 % \end{array}$

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