If b<0, then the roots $x_1$ and $x_2$ of the equation $2x^2+6x+b=0$, satisfy the condition $\left(x_1/x_2\right)+\left(x_2/x_1\right)<k$ where k is equal to.

The discriminant of the quadratic equation 2x² + 6x + b = 0 is given by D = 36 – 8b > 0. Therefore, the given equation has real roots.

We have $\frac{x_1}{x_2}+\frac{x_2}{x_1}=\frac{x_1^2+x_2^2}{x_1{x}_2}=\frac{{\left(x_1+x_2\right)}^2-2x_1{x}_2}{x_1{x}_2}=\frac{(-3{)}^2-2(b/2)}{b/2}=\frac{18}{b}-2<-2$

$[\because b<0]$