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Q.

If b2-4ac0 then the roots of quadratic equation ax2+bx+c=0 is


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a

b2a+b2-4ac2a

b

-b2a-b2+4ac2a

c

b2a±b2+4ac2a

d

-b2a±b2-4ac2a  

answer is D.

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Detailed Solution

It is given that for the equation ax2+bx+c=0 , b2-4ac0.
Here are the relations between roots and discriminant
       When roots are non-real, the discriminant is less than 0
       When roots are real and equal, the discriminant is equal to 0
       When the roots real and unequal the discriminant is greater than 0
If b2-4ac0  then the roots are real and distinct,
Let the roots be α and β.
We know that,
α+β=-ba…..(1)
αβ=ca..(2)
We can write that,
(α-β)2=(α+β)2-4αβ Substituting the values of α+β and αβ in the above equation,
α-β=b2-4aca …… (3)
Adding equation 1 and 3, we get,
α=-b±b2-4ac2a Hence, by using quadratic formula, we get the roots as
 -b±b2-4ac2a Hence, option 4 is correct.
 
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