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Q.

If |bcb2+bcc2+bca2+acacc2+aca2+abb2+abab|=64 then the value of ab + bc + ca is equal to 

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a

The value of 4f(2), where f(x) satisfies f(x)+f(11x)=1+xxR{0,1}

b

Number of values of θ in [0,2π) satisfying |sin3θ11cos2θ43277|=0

c

Number of real solutions of the equation xlog105+log102=x+log10(2x1)

d

The value of |sin2AcotA1sin2BcotB1sin2CcotC1| (given A + B + C = π ) 

answer is B.

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Detailed Solution

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|bcb2+bcc2+bca2+acacc2+aca2+abb2+abab|=64

(ab+bc+ca)3=64ab+bc+ca=4

A) x=2,12,1f(2)=34sinθ=0,12,324values in [0,2π)

C) log10(5x22x1)=xx=1

D) |sin2AcotA1sin2BcotB1sin2CcotC1|=0A+B+C=π

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