Q.

If bond dissociation energies of xy,x2 and  y2 (all gaseous diatomic molecules) are in the ratio of 1:1: 0.5 and ΔHf for the formation of xy is 200kJmol1, the bond dissociation energy of x2  will be ______

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answer is 800.

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Detailed Solution

X2+Y22XY ΔH=(BE)xx+(BE)yy2(BE)xy If  BEof(xy)=a,then  BE  of(xx)=a

And  BE  of  (yy)=a2

ΔHf(xy)=200kJ

        400=a2ora=+800kJ

The bond dissociation energy of  x2=800kJ/mol

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