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Q.

If bond enthalpies of N = N, H-H and N-H bonds are x1,x2 and x3 respectively, ΔHf∘ for NH3 will be:

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a

6x3−x1−3x2

b

3x3−12x1−32x2

c

12x1+32x2−3x3

d

x1+3x2−6x3

answer is B.

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Detailed Solution

Given equation,

12N2(g)+32H2(g)⟶NH3(g)

The enthalpy of fusion of NH3 is.

ΔHf=x12+3x22−3x3

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