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If
$\begin{aligned} C (diamond) \to C (graphite) + {XkJmol}^{- 1} \\ C (diamond) + O_{2} (g) \to {CO}_{2} (g) + {YkJmol}^{- 1} \\ C (graphite) + O_{2} (g) \to {CO}_{2} (g) + {ZkJmol}^{- 1} \end{aligned}$
At constant temperature. Then

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X = Y + Z

–X = Y + Z

X = –Y + Z

X = Y – Z

answer is D.

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X = Y – Z

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