If C→=A→−B→ , then:

C¯=A¯−B¯ C¯×C¯=(A¯−B¯)×C¯ O=A¯×C¯−B¯×C¯ A¯×C¯=B¯×C¯

If C→=A→−B→ , then:

C¯=A¯−B¯ C¯×C¯=(A¯−B¯)×C¯ O=A¯×C¯−B¯×C¯ A¯×C¯=B¯×C¯

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If $\vec{C} = \vec{A} - \vec{B}$ , then:

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| \vec{A} - \vec{B} | > | \vec{A} | - | \vec{B} |

\vec{B} \times \vec{A} = \vec{C} \times \vec{A}

\bar{A} \times \bar{B} = \bar{B} \times \bar{C}

\bar{A} \times \bar{C} = \bar{B} \times \bar{C}

answer is A.

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\bar{C} = \bar{A} - \bar{B}

$\bar{C} \times \bar{C} = (\bar{A} - \bar{B}) \times \bar{C}$

$O = \bar{A} \times \bar{C} - \bar{B} \times \bar{C}$

$\bar{A} \times \bar{C} = \bar{B} \times \bar{C}$

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If C→=A→−B→ , then:

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If $\vec{C} = \vec{A} - \vec{B}$ , then: