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Q.

If chord joining t1 and t2 on the parabola y2=4ax is a focal chord then t1t2=

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a

2

b

1

c

0

d

1

answer is C.

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Detailed Solution

The equation of the chord joining t1 and t2 on the parabola y2=4ax y(t1+t2)=2x+2at1t2(1)

Given equation (1) passes through focus (a,0)

O=2a+2at1t2t1t2=1

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