If compound of reaction with B following first order with rate constant, 2.011×10−3 s−1. The time taken by A (in seconds) to reduce from 7g to 2 g will be (nearest integer) (log 5=0.698; log 7=0.845; log 2=0.301)

A+B→P t=0 7g t=t 2gAt constant volumet=2.303klogA0A t=2.3032.011×10-3log72 t=622.989 t≅623

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If compound of reaction with B following first order with rate constant, $2.011 \times 10^{- 3} s^{- 1} .$ The time taken by A (in seconds) to reduce from 7g to 2 g will be (nearest integer) $(\log 5 = 0.698; \log 7 = 0.845; \log 2 = 0.301)$

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answer is 623.

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$A + B \to P t = 0 7 g t = t 2 g$

At constant volume

$t = \frac{2.303}{k} \log \frac{{[A]}_{0}}{[A]} t = \frac{2.303}{2.011 \times 10^{- 3}} \log \frac{7}{2} t = 622.989 t ≅ 623$

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