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Q.

If coordinate of point P is (2, 3, 4) then OP vector is

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a

0i^ + 0j^ + 0k^

b

2i^ + 3j^ + 4k^

c

i^ + j^ + k^

d

-2i^-3j^-4k^

answer is B.

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Detailed Solution

OP=Position of P-Position of O

= 2i^ + 3j^ + 4k^ - (0i^ + 0j^ + 0k^)

=2i^+3j^+4k^

we know, position of point (a, b, c) is ai^ + bj^ + ck^.

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