Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

If cos-1x-cos-1y2=θ; then 4x2-4xy cos θ+y2=

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

4 sin2θ

b

2 sin2θ

c

14 sin2θ

d

4 sin 2θ

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

cos-1x=θ+cos-1y/2 x=cosθ.y/2-sinθ 1-y24 x2-2cos θy/2x+cos2θ. y24=sin2θ1-y24 4x2-4xycosθ+y2=4sin2θ

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon