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Q.

If cosθ4sinθ=1 then sinθ+4cosθ=

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Detailed Solution

 Let   sinθ+4cosθ=x.Then  (cosθ4sinθ)2+(sinθ+4cosθ)=1+x2cos2θ+16sin2θ+sin2θ+16cos2θ=1+x2x2=16x=±4.

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If cosθ−4sinθ=1 then sinθ+4cosθ=