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Q.

If cosx+cosy=45,cosxcosy=27, then 14tanxy2+5cotx+y2=

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a

0

b

1/4

c

3/4

d

5/4

answer is A.

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Detailed Solution

cosx+cosycosxcosy=1452cosx+y2cosxy22sinx+y2sinxy2=14514tanxy2+5cotx+y2=0

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If cos⁡x+cos⁡y=45,cos⁡x−cos⁡y=27, then 14tan⁡x−y2+5cot⁡x+y2=