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If $\cot 50^{o} = k$ then $\tan 85^{o} + \tan 5^{o}$

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$\frac{1 - k^{2}}{1 + k^{2}}$

$2 (\frac{1 - k^{2}}{1 + k^{2}})$

$(\frac{1 + k^{2}}{1 - k^{2}})$

$2 (\frac{1 + k^{2}}{1 - k^{2}})$

answer is D.

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Detailed Solution

$\cot 50^{o} = k \tan 85^{o} + \tan 5^{o} = 2 \cos e c 10^{o} = 2 \sec 80^{o} = \frac{2 (1 + \tan^{2} 40)}{(1 - \tan^{2} 40)} = 2 (\frac{1 + k^{2}}{1 - k^{2}})$

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