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Q.

If CP and CV denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

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a

CpCv=R

b

CpCv=28R

c

CpCv=R/28

d

CpCV=R/14

answer is C.

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Detailed Solution

Suppose specific heat per unit mole = S 
We know that SpSV=R
or   M0CpCV=R           ...(1)
where S=M0C
From eq. (1), we get
CpCV=RM0=R28         ...(2)
where Mo = Molar mass = 28 for nitrogen.
 

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