If ${[C u {(H_{2} O)}_{4}]}^{2 +}$ absorbs a light of wave length 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for ${[C u {(H_{2} O)}_{6}]}^{2 +}$ will be____ $\times 10^{- 21} J$ [Nearest integer]
$(G i v e n : h = 6.63 \times 10^{- 34} J s a n d C = 3.08 \times 10^{8} m s^{- 1})$

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answer is 766.

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Detailed Solution

$Δ_{t} = \frac{h c}{λ} = \frac{6.63 \times 10^{- 34} \times 3.08 \times 10^{8}}{600 \times 10^{- 9}}$
$= 3.4034 \times 10^{- 19} J = 340.34 \times 10^{- 21} J$

$Δ_{t} = \frac{4}{9} Δ_{0} \Rightarrow Δ_{0} = \frac{9}{4} Δ_{t} = \frac{9}{4} \times 340.34 \times 10^{- 21}$
$= 765.765 \times 10^{- 21} = 766 \times 10^{- 21}$