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Q.

If current in the branch of a circuit shown in figure is decreasing at a rate of 1.0 A/S, The potential difference Va-Vb at this instant is

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a

35 V 

b

25 V

c

10 V

d

20 V

answer is A.

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Detailed Solution

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VL=Ldidt=5×1V=+5volt, Now, Va60+5+20=Vb VaVb=35V 

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