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Q.

If d=123×57 is expressed as a terminating decimal, how many non-zero digits will d have?


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a

4

b

2

c

1

d

3 

answer is B.

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Detailed Solution

Given, d=123×57.
We have to find the number of non-zeros in the given rational number.
Multiply and divide by 24 to equalise the power in the denominator,
d=2423×57×24
d=1627×57 d=16107 d=0.0000016
Therefore, will have two non-zero digits, 1 and 6, when expressed as a decimal.
Hence, option 2 is correct.
 
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