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Q.

If D,E,F be the mid points of the sides BC,AC,AB respectively and AD=8,BE=4 and CF=20 then  AB2+BC2+CA2=

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a

50/3

b

70/3

c

200/3

d

400/3

answer is D.

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Detailed Solution

AD=8,BE=4,CF=20AB2+BC2+CA2=43AD2+BE2+CF2
=43[64+16+20]=43(100)=4003

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