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If density of water is $ρ$ , density of air is $σ$ and coefficient of viscosity of air is ‘ $η$ ’ then terminal velocity of a rain drop of radius ‘r’ is

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$\frac{2}{9} r^{3} (\frac{ρ - σ}{η}) g$

$\frac{9}{2} r^{2} (\frac{ρ - σ}{η}) g$

$\frac{2}{9} r^{2} (\frac{ρ - σ}{η}) g$

$\frac{9}{2} \frac{η r^{2}}{(ρ - σ)} g$

answer is C.

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$V = \frac{2}{9} \frac{r^{2} (ρ - σ) g}{η}$

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